Question
A mixture contains milk and water in the ratio 9 : 7. If
it contains 4 litres more milk than water, then find the quantity of milk (in litres) in the mixture.Solution
Let the quantity of milk be 9x liters and the quantity of water be 7x liters. Given that the quantity of milk is 4 liters more than the quantity of water: 9x = 7x +4 Solving for x, ATQ- 9x-7x=4 2x = 4 x=2 Therefore, the quantity of milk in the mixture is: 9x=9x2 = 18 liters So, the quantity of milk in the mixture is 18 liters.
Simplify:
6x + 8y - [(12x + 6y) - (4x + 3y) + 2y] - 4xIf 9x2 + 16y2 = 24xy, then find the ratio of ‘x’ and ‘y’, respectively.
- Suppose [a + (1/16a)] = 3, then the value of [16a³ + (1/256a³)] is:
If, 6x + y = 20, and 2xy = 32, and 6x > y, then find the value of 216x³ – y³.
If x + 1/x = 2, find x⁷ + 1/x⁷.
(x – 6) 2 + (y + 2) 2 + (z – 4) 2 = 0, then find the value of 4x - 3y + z.
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