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    5. If 3x + 2y = 13 and y² – 4y + 4 = 0, then find (x, y)

    Question

    If 3x + 2y = 13 and y² – 4y + 4 = 0, then find (x,

    y)
    A (4, 2) Correct Answer Incorrect Answer
    B (5,–1) Correct Answer Incorrect Answer
    C (2, 3) Correct Answer Incorrect Answer
    D (3, 2) Correct Answer Incorrect Answer

    Solution

    y² - 4y + 4 = 0 ⇒ (y-2)2 = 0 y = 2 Now, 3x + 2y = 13 3x + 2 x 2 = 13 3x = 9 ⇒ x = 3   (x,y) is (3,2).

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    • RRB NTPC

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