Question
If 3x + 2y = 13 and y² – 4y + 4 = 0, then find (x,
y)Solution
y² - 4y + 4 = 0 ⇒ (y-2)2 = 0 y = 2 Now, 3x + 2y = 13 3x + 2 x 2 = 13 3x = 9 ⇒ x = 3  (x,y) is (3,2).
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