Question
The least number which on being divided by 2, 3, 4, 5,
and 6 leaves a remainder of 1 but no remainder when divided by 7 is:Solution
LCM of 2, 3, 4, 5, and 6 =60 ATQ- The number will be divided by 7 and divided by 2,3,4,5,6 leaves the remainder 1. 60×5+1=301.
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