Question
Find the least multiple of 7 which when divided by 6, 8,
and 12 leaves 1 as the remainder.Solution
LCM of 6,8,12 =24. If LCM is multiplied by 2 then – 24×2 =48 For remainder 1- 48+1=49. 49 is the least multiple of the 7 which divided by 6,8,12 leaves 1 as a remainder.
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