Question
log (402- 202) is equal to
Solution
Considering the given equation log (402 - 202) β (402 - 202) = (40 + 20) (40 - 20) β (402 - 202) = 60 Γ 20 Now, log (402 - 202) = log (60 Γ 20) β log (60 Γ 20) = log 60 + log 20 β΄ Required value is log 60 + log 20
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