Question
The expression (x-β2)(x-β4) goes through its minima at the value of x =
a. Find the value of 2a - β2
Solution
(x - β2)(x - β4) = x2 β x(β2 + 2) + 2β2Β For value to be minimum, => d(x2Β β x(β2 + 2) + 2β2Β )/dx = 0 at x = a β 2xΒ βΒ β2Β β 2 = 0 => x = a So, 2aΒ ββ2 = 2 β΄ 2a ββ2 = 2
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