Question
If a and b are two real numbers such that b > a, ab < 0,
the sum of their squares is 458 and the difference between their squares is 120, then find the value of a - b.Solution
a2 + b2 = 458 ------- (i) a2 - b2 = 120 ------- (ii) By adding (i) and (ii), 2a2 = 578 a = ± 17 b = ± 13 We know, b > a and ab < 0. So, a = - 17 and b = 13 Thus, => a - b = - 17 - 13 = - 30Â
More Previous year papers Questions
1885 ÷ 64.98 + 7.29 + ? = 69.09
212 + 14 × 23 – 28 × 15 = ? Â
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567-4824 ÷ 134 =? × 9
Determine the value of 'p' in the expression.
28 ÷ 22p + 1 = 43Â
What will come in place of (?) in the given expression.
(15) ² - (13) ² = ?? = 6.25% of 240 + 25 2 + 17 2 – 16 × 17
35% of 840 + 162 = ? – 25% × 300
(7/5) × (3/4) × (5/9) × (6/7) × 3112 = ?
1024 ÷ 16 + 800 ÷ √64 + ? = 200 * 2
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