Question
60 percent students in a school are boys. 40 percent
boys passed in the examination. If 35 percent of total students passed the examination, then what percent of girls failed the examination?Solution
Let the total number of students in the school be 1000. Number of boys = 60% of 1000 = 600 Then, number of girls = 1000 - 600 = 400 Number of boys who failed the exam = (100 - 40)% of 600 = 360 Number of students who failed = (100 - 35)% of 1000 = 650 Then, number of girls who failed = total fail - boys who failed = 650 - 360 = 290 girls Percentage of girls who failed = (failed girls/total girls) × 100 = (290/400) × 100 ∴ Percentage of girls wo failed is 72.5%.
If sin(3θ) = cos(2θ), then find the value of θ between 0 and 90 degrees.
The angle of elevation of the top of a 70 feet tall tower from the initial position of a person on the ground was 30°. She walked towards the tower in ...
cot 4˚ x cot 47˚ x cot 42.3˚ x cot 43˚ x cot 47.7˚ x cot 86˚= ?
[(sinx – 2sin 3 x)/(2cos 3 x – cosx)] 2 + 1, x ≠45 o , is equal to:
Find the Value of Sin⁶`Theta` + Cos⁶`Theta` + 3Sin² `theta` Cos²`Theta`
- In a triangle ABC, if 5∠A = 3∠B = 15∠C, then find the value of cosA + sin(C + 10 ° )
sin2 4˚ + sin2 6˚ + sin2 8˚ + sin2 10˚ + ……… + sin2 86˚ =?
The minimum value of 77 sin θ + 36cosθ is