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    5. If x = 7 + 4√3 and xy = 1, then the value of (1x2+1y2)(1x2+1y2) is -

    Question

    If x = 7 + 4√3 and xy = 1, then the value of

    (1x2+1y2)(1x2+1y2) is -
    A 7+43√7−43√7+437−43 Correct Answer Incorrect Answer
    B 85√3 Correct Answer Incorrect Answer
    C 57 Correct Answer Incorrect Answer
    D 194 Correct Answer Incorrect Answer

    Solution

    The correct answer is D

    Practice Next
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    Relevant for Exams:

    • SBI PO
    • IBPS RRB PO

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