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      Question

      If x = 7 + 4√3 and xy = 1, then the value of

      (1x2+1y2)(1x2+1y2) is -
      A 7+43√7βˆ’43√7+437βˆ’43 Correct Answer Incorrect Answer
      B 85√3 Correct Answer Incorrect Answer
      C 57 Correct Answer Incorrect Answer
      D 194 Correct Answer Incorrect Answer

      Solution

      The correct answer is D

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