Question
The population of a town increases by 20% annually. If
its present population is 864000, then what was the difference between its population 2 years ago and 1 year ago?Solution
Present population = 864000 Population before 1st year = 1/1.2 × 864000 = 72000 Population before 2nd year = 1/1.2 × 72000 = 60000 Therefore, required difference = 720000 - 60000 = 120000
A certain sum of money invested at R% p.a. fetches a compound interest (compounded annually) of 1525.5 and simple interest of Rs.1500 at the end of 2 ye...
Naina lent Rs. 9,800 to Mohini for 4 years and Rs. 8,800 to Mitali for 6 years on simple interest at the same rate of interest and received Rs. 11,040 i...
A person invested a sum of Rs. 9000 at r% per annum at simple interest and a sum of Rs. 13500 at (r-4)% at simple interest. If total interest earned on ...
A sum of money doubles itself in 5 years in how many years it will be 3 times?
What will be the ratio of simple interest earned by certain amount at the same rate of interest for 4 years and 6 years ?
Find the total amount returned by Manish to the bank at the end of three years, when Rs.24000 is borrowed at the rate of (25/2)% compounded annually?(ca...
Simica invested a certain amount of money at a simple interest rate of 12.5% per annum and earned Rs. 2,400 as interest over 3 years. If Tabu invested t...
A sum of money lent at 5% rate of simple interest. The difference between interest for 6 years and 4 years is Rs. 2000. Find the principal amount.
An initial principal sum of Rs. 8000, invested by Pranav, accrued interest at a compound rate of 20% annually for a period of 2 years. Subsequently, the...
If Rs. 15000 is invested at 14% per annum, compounded yearly, calculate the interest earned in one year.