Question
P and Q can do a piece of work in 20 days and P alone
can do it in 30 days. In how many days can B do it alone.Solution
ATQ, (Efficiency = work/Time) The efficiency of P and Q in 1 day is = 1/20 The efficiency of P in 1 day = 1/30 Therefore the efficiency of Q in 1 day is = (1/20) – (1/30) = (1/60) Therefore Q will take 60 days to complete.
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