Start learning 50% faster. Sign in now
Let CE is a pole of height h meter. AD is a hill of height 200m. Let distance between bottom of hill to pole = x m. According to question ∠XAC=300=∠CB and ∠XAE=600=∠AED From right angled ΔADE tan 600=AD/DE √81=(200/x) X = (200/√3) m From right angled ΔABC Tan300 = (AB/BC) = (AB−BD)/x (1/√3)= (200−h)/x X = √3(200−h) (200/√3)= √3(200−h) (200/3) = (200−h) h = 200−(200/3) = (600−200)/3 = 400/3 = 133.33m Hence, height of pole =133.33m
Ratio of cost price and marked price of an article is 1:3. If profit obtained is Rs. 3500 then the profit percentage is 50%. If discount is 10%, find th...
A watch is sold at a profit of 20%. If both the cost price and selling price are reduced by Rs. 100, then the profit would be 5% more. Find the original...
A table is marked (z+5)% above its cost price and a discount of 35% was given on it while selling. If the cost price of the table is Rs. 1485 more than ...
Abhinav bought some pencils for ₹ X. He sold 20% of pencils at 25% loss, one third at 20% profit and the remaining at 25% profit. If the total profit ...
To clear his stock of rice, Sunil starts giving 1.2 kg of rice to customers in place of 1 kg. However, he secretly uses an 800-gram weight instead of a ...
An item's label price is 40% more than its original price. The shopkeeper manages to earn 30% profit on it. If the label price exceeds the sale price by...
A shopkeeper sells an item at a profit of 25% and dishonestly uses a weight that is 30% less than the actual weight. Find his total profit%.
Neeraj and Dheeraj are two friends. Neeraj calculates his profit % on the selling price while Dheeraj calculates his profit % on the cost price. If both...
A man purchased an article for Rs 2,000. He sold it to the first customer at a 10% loss, and the first customer then sold it to the second customer at a...
A product is sold for ₹1050, but its marked price is ₹1400. Calculate the discount percentage given by the shopkeeper.