Question
A hemispherical tank full of water is emptied by a pipe
at the rate of 23.1 litres per second. How much time (in hours) will it take to empty 3/4Â th part of the tank if the internal radius of the tank is 21 m?Solution
The volume of the hemispherical tank is 3/4 à 22/7 à 21 à 21 à 21 21829.5 m3 The capacity of the tank is 21829.5à 1000 L 21829500 L So, Time taken by the pipe emptied 2/3 part of the tank is (3/4 à 21829500) á 23.1sec 708750 sec Time in hours 708750/3600 (1575/8) hours ⴠThe required time is (1575/8) hours
(500 Ă 6 á 10) - (â256 + 8) = ?
22% of 400 +Â â ? = 34% of 800 - 25% of 400
(2/5)(32% of 4500 â 440) = ? Ă 8
1550 á 62 + 54.6 x 36 = (? x 10) + (28.5 x 40)     Â
What will come in the place of question mark (?) in the given expression?
96 á (9 - 6.6) + 17.5 X 6 = ? á 8Â
13 X ? = 85 X 4 + â81 + 2
45% of 360 - 160 + ? = â324
((67)32 × (67)-18 / ? = (67)â¸
4567.89 - 567.89 - 678.89 = ?
82.3 Ă 644.7 Ă 723.4 Ă 815.85 = 72?
