Question
The average of 20 numbers is 32. If two numbers are 29
and 31, then what is the average of the remaining numbers (correct up to two decimals)?Solution
ATQ, we can say that Total of 32 numbers = = 20 × 32 = 640 After removing 29 and 31 new total = 640 - (29 + 31) = 640 - 60 = 580 New average = 580/18 = 32.22
7, 14, 42, 210, 1470, ?
A sequence {Vₙ} is defined for n ≥ 1 by:
I) For every n ≥ 3: Vₙ = 2Vₙ₋₁ − Vₙ₋₂ + 4
It is known that - V₃ = 22 and ...
12, 20, 36, ?, 132, 260
If 6 4 x 5.75 9,
Then, (x²-1) = ?
...12 13 30 �...
112 162 199 ? 242 252
...21 11.5 13 ? 45.5 116.75
...171, 173, 183, 213 , ‘?’, 411, 633.
114 106 102 100 99 ?
...Choose the correct alternative
21: 3 ∷ 574: ?