Question
A circle touches all four sides of a quadrilateral ABCD.
If AB = 18 cm, BC = 21 cm and AD = 15 cm, then length CD is:Solution
If we have a circle onside the quadrilateral, then sum of the opposite side of Quadrilateral is equal. So, AD + BC = AB + CD 15 + 21 = 18 + CD 36 = 18 + CD CD = 18 cm
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