Question
If cos q = 5/13 , then the value of tan2q +
sec2q is equal to:Solution
tan2q + sec2q sec² q - 1 + sec² q = 2sec² q - 1 Given sec q = 13/5 = (2 x 169)/25 - 1 =(338/25)-1  = (338-25)/25 = 313/25 The value of tan² q + sec² q is 313/25.
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