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      Question

      Pipe ‘X’ and pipe ‘Y’ can fill a tank alone in

      36 hours and 18 hours, respectively. If both pipes are opened together and pipe ‘Y’ is closed after 6 hours, then find the time taken by pipe ‘X’ to fill the remaining portion of the tank alone.
      A 18 hours Correct Answer Incorrect Answer
      B 24 hours Correct Answer Incorrect Answer
      C 15 hours Correct Answer Incorrect Answer
      D 12 hours Correct Answer Incorrect Answer

      Solution

      Let the capacity of the tank be 36 units (LCM of 36 and 18) Efficiency of pipe ‘X’ = 36 ÷ 36 = 1 unit/hour
      Efficiency of pipe ‘Y’ = 36 ÷ 18 = 2 unit/hour Let pipe ‘X’ fill the remaining portion in x hours. ATQ, 6 × (1 + 2) + 1x = 36 Or, 18 + x = 36 Or, x = 18 Therefore, required time taken = 18 hours

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