Question
Pipe βXβ and pipe βYβ can fill a tank alone in
36 hours and 18 hours, respectively. If both pipes are opened together and pipe βYβ is closed after 6 hours, then find the time taken by pipe βXβ to fill the remaining portion of the tank alone.Solution
Let the capacity of the tank be 36 units (LCM of 36 and 18) Efficiency of pipe βXβ = 36 Γ· 36 = 1 unit/hour
Efficiency of pipe βYβ = 36 Γ· 18 = 2 unit/hour Let pipe βXβ fill the remaining portion in x hours. ATQ, 6 Γ (1 + 2) + 1x = 36 Or, 18 + x = 36 Or, x = 18 Therefore, required time taken = 18 hours
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