Question
Tap A is 100% more efficient than tap B. Both the taps
together can fill the tank in 6 hours. Find the time taken by tap C, which is 50% more efficient than tap B, to fill the tank alone.Solution
Let, time taken by tap B to fill the tank be x hours,
So, time taken by tap A to fill the tank = x/2 hours According to question, 1/x + 1/(x/2) = 1/6
1/x + 2/x = 1/6
x = 18 So, time taken by tap C to fill the tank = 18/1.5 = 12 hours
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