Question
Pipe ‘A’ can fill a tank in 27 hours. Pipe ‘B’
can empty it in 54 hours. If both are opened simultaneously, in how many hours will 66.67% of the tank be filled?Solution
Let the capacity of the tank be 108 litres. So, efficiency of pipe ‘A’ = 108 ÷ A = 4 litres/hour And efficiency of pipe ‘B’ = 108 ÷ B = 2 litres/hour So, combined efficiency of both pipes = 4 – 2 = 2 litres/hour So, time taken to fill 66% of the tank = (108 × 0.67) ÷ 2 = 72 ÷ 2 = 36 hoursÂ
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