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    Question

    Tap A can fill a tank in 8 hours. Tap B can fill 20%

    part of the same tank in 4 hours, whereas Tap C can alone empty a tank in тАШxтАЩ hours. 4/7 part of the tank is filled in 8 hours, when all three taps are opened together. How much time (in hours) will Tap A and C together will take to fill 30% part of the tank?
    A 14 hours Correct Answer Incorrect Answer
    B 16 hours Correct Answer Incorrect Answer
    C 18 hours Correct Answer Incorrect Answer
    D 20 hours Correct Answer Incorrect Answer
    E None of these Correct Answer Incorrect Answer

    Solution

    ┬аTap A alone can fill the tank in = 8 hours. Tap B alone can fill the tank in = (5/1)┬а├Ч┬а4 = 20 hours Tap C alone can empty the tank in = x hours (A + B +C) together can fill the tank in = 8┬а├Ч┬а(7/4) = 14 Taking LCM of 8, 20 and 14 = 280 Efficiency of Tap A = 35 Efficiency of Tap B = 14 Efficiency of Taps (A + B +C) = 20 Efficiency of Taps (A +C) = 20 тАУ 14 = 6 Tap A and C together take to fill 30% part of the tank in, => (30/100)┬а├Ч (280/6) = 14 hours

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