Question
Tap A can fill a tank in 8 hours. Tap B can fill 20%
part of the same tank in 4 hours, whereas Tap C can alone empty a tank in ‘x’ hours. 4/7 part of the tank is filled in 8 hours, when all three taps are opened together. How much time (in hours) will Tap A and C together will take to fill 30% part of the tank?Solution
 Tap A alone can fill the tank in = 8 hours. Tap B alone can fill the tank in = (5/1) × 4 = 20 hours Tap C alone can empty the tank in = x hours (A + B +C) together can fill the tank in = 8 × (7/4) = 14 Taking LCM of 8, 20 and 14 = 280 Efficiency of Tap A = 35 Efficiency of Tap B = 14 Efficiency of Taps (A + B +C) = 20 Efficiency of Taps (A +C) = 20 – 14 = 6 Tap A and C together take to fill 30% part of the tank in, => (30/100) × (280/6) = 14 hours
More Pipes and cisterns Questions
- Which letter and number cluster will replace the question mark (?) to complete the given series?
LT6, KU12, IW24, FZ48, ____ - Which letter-cluster will replace the question mark (?) in the following series?
RGV, UME, ?, AYW, DEF - Which letter-cluster will replace the question mark (?) in the following series?
NPQR, OORQ, PNSP, ____, RLUN - A series is given with one term missing. Choose the correct alternatives from the given ones that will complete the series.
57, 59, 56, 61, 54, ___ - Select the number from among the given options that can replace the question mark (?) in the following series.
17, 18, 22, 31, 47, ___
Relevant for Exams:
