Question
Tap A can fill a tank in 15 hours. Tap B can fill 20%
part of the same tank in 4 hours, whereas Tap C can alone empty a tank in ‘x’ hours. 2/5 part of the tank is filled in 4 hours, when all three taps are opened together. How much time (in hours) will Tap A and C together will take to fill 20% part of the tank?Solution
 Tap A alone can fill the tank in = 15 hours. Tap B alone can fill the tank in = (5/1) × 4 = 20 hours Tap C alone can empty the tank in = x hours (A + B +C) together can fill the tank in = 4 × (5/2) = 10 Taking LCM of 15, 20 and 10 = 60 Efficiency of Tap A = 4 Efficiency of Tap B = 3 Efficiency of Taps (A + B +C) = 6 Efficiency of Taps (A +C) = 6 – 3 = 3 Tap A and C together take to fill 20% part of the tank in, => (20/100) × (60/3) = 4 hours
How many boxes are there between Y and X?
The student who belongs to China appeared for which exam?
Who sits in front of Varun?
What is the number of boxes above Red box?
Which of the following box is kept immediate above box G?
Which one of the following is the specialization of Rahul?
Read the directions below and answer the following questions.
Six persons B, D, E, A, F, and C live in a six-floored building. The bottommost f...
A likes which of the following game?Â
How many box (es) were placed above the box which contained 35 Kg of Sugar?
Who went toHawaii?