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Let the capacity of the cistern = 180 units Then, efficiency of pipe ‘A’ = 180/20 = 9 units/minute Efficiency of pipe ‘B’ = 180/18 = 10 units/minute Efficiency of pipe ‘C’ = 180/12 = 15 units/minute So, combined efficiency of pipes ‘A’, ‘B’ and ‘C’ = 9 + 10 – 15 = 4 units/minute 50% of the cistern’s capacity = 90 units Therefore, time taken by all 3 pipes together to fill 50% of the cistern = 90/4 = 22.5 minutes
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