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Let the capacity of the cistern = 144 units Then, efficiency of pipe ‘A’ = 144/18 = 8 units/minute Efficiency of pipe ‘B’ = 144/16 = 9 units/minute Efficiency of pipe ‘C’ = 144/12 = 12 units/minute So, combined efficiency of pipes ‘A’, ‘B’ and ‘C’ = 8 + 9 – 12 = 5 units/minute 50% of the cistern’s capacity = 72 units Therefore, time taken by all 3 pipes together to fill 50% of the cistern = 72/5 = 14.4 minutes
Statements:
M > N = W; J < P = N; Y > P
Conclusions:
I. Y > W
II. M < Y
III. J > M
Statements: E & F, H # I, G $ F, E % D, G @ H
Conclusions:
I. D $ F
Statements: M ≤ N = O ≤ P; P = Q ≤ U; R > N = U
Conclusions:
I. R > O
II. U ≥ M
Statements:Q ≥ R,R < S,S < T
Conclusions: I. T > R II. Q ≥ T
Statements: S @ O, O & E, E $ K, K # C
Conclusions: I. S @ K II. K @ O III. C @ E
...Statements: K @ L; M & O, N % L, K $ O
Conclusions:
I. O @ L
II. M @ L
<...Statements: Z % Y; X # W; U % V; W & V; Y @ X
Conclusions:
Statements: R < S > T; U < V ≤ S; R > P
Conclusions:
I. S > P
II. U < R
III. T < P
