Question
Pipes ‘A’ and ‘B’ can fill a tank in 6 hours and
9 hours, respectively. If pipe ‘C’ is opened along with pipes ‘A’ and ‘B’, then the tank gets filled in 6 hours. Find the time taken by pipe ‘C’ to empty (5/6)th part of the same tank.Solution
Let capacity of the tank = 18 litres (lcm of 6 and 9) Efficiency of pipe ‘A’ = (18/6) = 3 litres/hour Efficiency of pipe ‘B’ = (18/9) = 2 litres/hour Efficiency of all the three pipes together = (18/6) = 3 litres/hour Efficiency of pipe ‘C’ = 3 – (3 + 2) = (-2) litre/hour {Negative sign shows that pipe ‘C’ is an outlet pipe} Required time taken = {(5/6) × 18)}/2 = 7.5 hours
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Statement:
P < M ≤ Y = X; U > A =C; P < C = O > E
Conclusions:
I). Y > C
II). X < E
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