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Let the total capacity of tank be 150 units Efficiency of pipe ‘A’ = 150/25 = 6 units/hour Efficiency of pipe ‘B’ = 150/30 = 5 units/hour Tank filled in 2 hours = (6 – 5) = 1 units Therefore, tank filled in (2 × 30 = 60 hours) = 1 × 30 = 30 units Required percentage of tank filled = (30/150) × 100 = 20%
(9.013 – 15.04) = ? + 9.98% of 5399.98
40.05% of 210.05 – 10.15% of 109.99 × 5.02 = ?
17.06 2 + √36.08 – (4.04/2.99) × 3.02 × 4.92 = ? × 4.99
509.85 ÷ 15.05 + 210.16 – 18.06 × 5.95 = ?
139.88% of 119.89 + 1451.89 ÷ 6.01 - √196.01 = ? ÷ 3.01 + 215.98
`sqrt(1297)` + 189.99 =?
25.02% of 460.02+?% of 300.02=295.21
35.1% of 1599 = ?–(449.96 ÷ 6.12) × 2
(11.98% of 449.99) - 3.998 = √?