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Let A be closed after x minutes. Then, Part filled by (A + B) in x min. + part filled by B in (12 – x) min. = 1 x (1/12 + 1/16 ) + (12 – x ) × 1/16 = 1 ⟹ (7 x)/48 + (12 - x)/16 = 1 ⟹ (7 x)/48 + 3/4 - x/16 = 1 ⟹ (4 x)/48 = 1/4 ∴ x = 3 ∴ Hence, A must be closed after 3 minutes.
Find the value of (cos 60 º + sin 60 º) /(tan 60 º + cot 45 º) .
If sin θ = 3/5 and cos θ = 4/5, find the value of (2tan² θ + 3cot² θ).
If cosec (2A + B) = (2/√3) and cosec (A + B) = √2, then determine the value of (4A - B).
If sin 28° = 15/17 , then tan 62° = ?
tan 1˚ × tan 2˚× …………………….tan 88˚ × tan 89˚ = ?
If 2cosA + secA = 2√2 , 0° < < 90°, then the value of 2(sec 4 A + cosec 4 A) is: