Question
Two pipes A and B can fill a tank in 12 min., and 16
min, respectively. If both the pipes are opened simultaneously, after how much time A should be closed so that the tank is full in 12 minutes?Solution
Let A be closed after x minutes. Then, Part filled by (A + B) in x min. + part filled by B in (12 – x) min. = 1 x (1/12 + 1/16 ) + (12 – x ) × 1/16 = 1 ⟹ (7 x)/48 + (12 - x)/16 = 1 ⟹ (7 x)/48 + 3/4 - x/16 = 1 ⟹ (4 x)/48 = 1/4 ∴ x = 3 ∴ Hence, A must be closed after 3 minutes.
More Pipes and cisterns Questions
√3598 × √(230 ) ÷ √102= ?
3/7 of 686 + 133(1/3)% of 33 – 69 =?
Solve the following:
240 ÷ 4 × 512 ÷ 8
((12+12+12+12)÷4)/((8+8+8+8+8+8)÷16) = ?
- What will come in place of the question mark (?) in the following questions?
(?)2 = {(26% of 35% of 3000) ÷ 3} × 91
242 + 80% of 1620 = ? × 16 – 35% of 800
35% of 240 – 6 2 = ? 2 – √256
√? = 80% of 720 - 22% of 2500
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