Question
Two pipes P and Q can fill a tank in 48 minutes and 64
minutes respectively. If both the pipes are opened simultaneously, after how much time Q should be closed so that the tank is full in 36 minutes?Solution
Let Q be closed after x minutes. Then, Part filled by (P+Q) in x min. + part filled by P in (36 – x ) min. = 1 x(1/48 + 1/64) + (36 - x) x 1/48 = 1 ⟹(7x/192) + (36 - x)/48 = 1 ⟹ 7x + 4 (36 – x ) = 192 ∴ x = 16 ∴ Hence, Q must be closed after 16 minutes
More Pipes and cisterns Questions
√3598 × √(230 ) ÷ √102= ?
3/7 of 686 + 133(1/3)% of 33 – 69 =?
Solve the following:
240 ÷ 4 × 512 ÷ 8
((12+12+12+12)÷4)/((8+8+8+8+8+8)÷16) = ?
- What will come in place of the question mark (?) in the following questions?
(?)2 = {(26% of 35% of 3000) ÷ 3} × 91
242 + 80% of 1620 = ? × 16 – 35% of 800
35% of 240 – 6 2 = ? 2 – √256
√? = 80% of 720 - 22% of 2500
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