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Let the second pipe can fill tank in x hours So, first pipe fill tank in (x - 5) hours and Third pipe fill tank in (x + 5) hours According to the question, Second pipe and third pipe together take 1 hour more time to fill the tank from first pipe. So time taken by second pipe third pipe together = (x – 5 + 1) hours = (x – 4) hours 1/x + 1/(x+5) = 1/(x-4) (x +5+x )/(x2+ 5x) = 1/(x-4) (x – 4) (2x + 5) = x2+ 5x 2x2+ 5x - 8x – 20 = x2+ 5x x2- 8x – 20 = 0 x2- 10x + 2x – 20 = 0 x (x – 10) + 2 (x – 10) = 0 (x – 10) (x + 2) = 0 x = - 2, 10 So second pipe can fill the tank in 10 hours alone.
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