Total number of flowers = 3 + 2 =5 Let S be the sample space. Then, n(S) = total number of ways of selecting 3 flowers out of 5 = 5C3 = (5x4x3!)/(3!x2x1) = 10 Let E= event of selecting 3 flowers when none is a lily n(E) = 3C3 = 1 P (E) when none of the flowers is a lily = 1/10 P (E) when at least one flower is a lily = 1 - 1/10 = 9/10
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