Question
In how many ways can the selection of 4 boys and 3 girls
can be made from a group of 6 boys and 6 girls?Solution
Selection of 4 boys from 6 boys = 6C4 = 6!/(4! ×2!) = 15 Selection of 3 girls from 6 girls = 6C3 = 6!/(3! ×3!) = 20 Required number of ways = 15 × 20 = 300
More Permutation and combination Questions
√3598 × √(230 ) ÷ √102= ?
15% of 2400 + (√ 484 – √ 256) = ?
(13)2 - 3127 ÷ 59 = ? x 4
6269 + 0.25 × 444 + 0.8 × 200 = ? × 15
...(53 + 480 ÷ 4)% of 20 = ?% of 70
Find the simplified value of the following expression:
62 + 122 × 5 - {272 + 162 - 422}
(15 × 225) ÷ (45 × 5) + 480 = ? + 25% of 1240
√ [? x 11 + (√ 1296)] = 16
11 × 25 + 12 × 15 + 14 × 20 + 15 = ?
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