Question
In how many different ways can 6 boys and 3 girls to be
seated in a row such that all the boys seated together and all the girls seated together?Solution
Number of ways in which boy and girls can be seated = 6! ×3! Total number of ways when boys are seating together and girls are seating together = 2! × 6! × 3!
More Permutation and combination Questions
√3598 × √(230 ) ÷ √102= ?
15% of 2400 + (√ 484 – √ 256) = ?
(13)2 - 3127 ÷ 59 = ? x 4
6269 + 0.25 × 444 + 0.8 × 200 = ? × 15
...(53 + 480 ÷ 4)% of 20 = ?% of 70
Find the simplified value of the following expression:
62 + 122 × 5 - {272 + 162 - 422}
(15 × 225) ÷ (45 × 5) + 480 = ? + 25% of 1240
√ [? x 11 + (√ 1296)] = 16
11 × 25 + 12 × 15 + 14 × 20 + 15 = ?
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