Question
Seven musicians out of which 3 are from the same band
and the rest are solo artists are to be seated in a row. Find the number of ways in which the three band members do not sit together.Solution
Total number of arrangements = 7! = 5040 ways
Group the 3 band members: arrangements within group = 3! = 6 ways
Arrange 5 items = 5! = 120 ways
Therefore, required number of ways = 5040 – (6 × 120) = 4320 ways
Solve the following equation:
48 ÷ [35 – {30 – (31 – 26 ÷ 2 × 4)}]
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