Question
Four mobile phones are kept on display in a mobile
shop. The price of the costliest mobile phone is nine times the cost of the cheapest mobile phone. The price of the second most costly mobile phone is Rs. 62,000 which is 25% more than the mobile phone which costs more than only one phone. If the total cost of the cheapest and the costliest mobile phone is 1,04,250, then find the average of all the mobile phones. ÂSolution
Average of all the phones= (10425+49600+62000+93825)/4 Â = 215850/4 = 53962.5
Statements: L < E; M = O; E >K ≥ M
Conclusions:
I. L < M
II. K = O
In the following question the relationship between different elements is given in the statements followed by three conclusions I, II and III. Read the ...
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Conclusions: I. J < M II. L = J
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