Question
A sum of Rs. 9,200 was divided between 'A' and 'B' such
that the amount received by 'B' was 30% more than that by 'A'. If 'A' and 'B' spent 10% and 25% of the respective amounts received by them, then find the sum of amounts spent by 'A' and 'B' together.Solution
Let the amount received by ‘A’ = Rs. ‘10x’ Then amount received by ‘B’ = 10x × 1.3 = Rs. ‘13x’ we have, 10x + 13x = 9200 So, x = 9200 ÷ 23 = 400 So, amount received by ‘A’ = 10 × 400 = Rs. 4,000 Amount received by ‘B’ = 13 × 400 = Rs. 5,200 Amount spent by ‘A’ = 4000 × 0.1 = Rs. 400
Amount spent by ‘B’ = 5200 × 0.25 = Rs. 1,300 So, required sum = 400 + 1300 = Rs. 1,700
(2 ÷ 3) × (4 ÷ 12) × (? ÷ 10) × 45 × (1 ÷ 5) = (? ÷ 6) + (2 ÷ 5)
46% of 13/92 × 24/91 × 3500 =?
40% of (34 x 25) + 105 = ?
What is the value of 143 + 163 + 183 + … + 303?
125 + 30% of 250 + √576 = ?
((9.77)0- 〖(0.1)〗(-1))/(〖(6/24 )〗(-1) ×(3/2)3+ 〖((-2)/6)〗(-1) ) = ?
...Train M, ‘x’ metres long crosses (x – 30) metres long platform in 22 seconds while train N having the length (x + 30) metres crosses the same plat...
(3/7) of 700 + 33(1/3)% of 339 - 69 =?
Find the Value ofÂ
 `sqrt(7744)`   - `sqrt(4761)` + `sqrt(8281)`  + `sqrt(5625)` + ? = 1856Â