Question
‘P’ and ‘Q’ are two points 12 cm apart. A point
‘R’ is located on PQ such that PR is 7 cm. If PR is increased by 20%, by what percentage does the length of QR decrease?Solution
ATQ,
PQ = 12 cm
PR = 7 cm
Therefore, QR = 12 – 7 = 5 cm
New PR = 1.20 × 7 = 8.4 cm
New QR = 12 – 8.4 = 3.6 cm
Percentage decrease = {(5 - 3.6)/5} × 100 = 28%
480 ÷ 10 + 18 % of 160 + ? * 9 = 60 * √36
`(sqrt(960.87)xx9.932+sqrt(629.998)xx26.385)/(sqrt(1028.902)xx4.977)=?`
What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)...
What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)...
(2100.23 ÷ 34.98) + (864.32 ÷ 23.9) + 1854.11 =?
- 29.98% of 249.897 = ?² – (4.98)²
What is the area (in cm²) of a square inscribed in a circle with a radius of 10√2 cm?
What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)...
What approximate value will replace the question mark (?) in the following?
29.99...
(363.89% of 224.98 – 319.86% of 134.94) ÷ ? = √(134.88 ÷ 15.25)