Question
‘P’ and ‘Q’ are two points 12 cm apart. A point
‘R’ is located on PQ such that PR is 7 cm. If PR is increased by 20%, by what percentage does the length of QR decrease?Solution
ATQ,
PQ = 12 cm
PR = 7 cm
Therefore, QR = 12 – 7 = 5 cm
New PR = 1.20 × 7 = 8.4 cm
New QR = 12 – 8.4 = 3.6 cm
Percentage decrease = {(5 - 3.6)/5} × 100 = 28%
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