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    Question

    ‘P’ and ‘Q’ are two points 12 cm apart. A point

    ‘R’ is located on PQ such that PR is 7 cm. If PR is increased by 20%, by what percentage does the length of QR decrease?
    A 28% Correct Answer Incorrect Answer
    B 32% Correct Answer Incorrect Answer
    C 12% Correct Answer Incorrect Answer
    D 18% Correct Answer Incorrect Answer
    E None of these Correct Answer Incorrect Answer

    Solution

    ATQ,

    PQ = 12 cm

    PR = 7 cm

    Therefore, QR = 12 – 7 = 5 cm

    New PR = 1.20 × 7 = 8.4 cm

    New QR = 12 – 8.4 = 3.6 cm

    Percentage decrease = {(5 - 3.6)/5} × 100 = 28%

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