Question
‘X’ owns 40% less pens than ‘Y’. ‘Y’ owns
50% more pens than ‘Z’. By what percentage are the pens with ‘X’ less than those with ‘Z’?Solution
ATQ,
Let, number of pens with ‘Y’ = 30a
Number of pens with ‘X’ = 0.6 × 30a = 18a
Number of pens with ‘Z’ = (30a/1.5) = 20a
So, required percentage = {(20a – 18a)/20a} × 100 = 10%
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