📢 Too many exams? Don’t know which one suits you best? Book Your Free Expert 👉 call Now!

  • google app store apple app store
  • ✖

      Question

      In a shop, there are a total of 15,000 chip packets. Out

      of these, 28% are Green Lays packets, and out of the remaining, 75% are Red Lays packets, and the rest are Blue Lays packets. If 20% of Green Lays packets, 10% of Red Lays packets, and 15% of Blue chip packets were rejected for quality, then how many chip packets, in total, were rejected for quality?
      A 210 Correct Answer Incorrect Answer
      B 115 Correct Answer Incorrect Answer
      C 250 Correct Answer Incorrect Answer
      D 2055 Correct Answer Incorrect Answer
      E none of these Correct Answer Incorrect Answer

      Solution

      ATQ, Number of Green lays packets in the shop = 15000 × 0.28 = 4200 Number of Red lays packets  in the shop = (15000 – 4200) × 0.75 = 8100 Number of Blue lays packets in the shop = 10800 – 8100 = 2700 Number of Green lays packets rejected for quality = 4200 × 0.20 = 840 Number of Red lays packets rejected for quality = 8100 × 0.10 = 810 Number of Blue lays packets rejected for quality = 2700 × 0.15 = 405 So, total number of chips packets rejected for quality = (840 + 810 + 405) = 2055

      Practice Next
      ask-question