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Let number of students in first school = x ⇒(60 x)/100 + 30 = x ⇒x – (60 x)/100 = 30 ⇒ (40 x)/100 = 30⇒ x = 75 ∴ Number of passed students = 75 -30 = 45 Number of students in second school = 75 + 25 = 100 Number of passed students = 45 + 20 = 65 ∴ Pass percentage of the latter school = 65%
I. x2 + (9x/2) + (7/2) = - (3/2)
II. y2 + 16y + 63 = 0
I. 2x² + 11 x + 15 = 0
II. 2y² - 19 y + 44 = 0
I. 5x² -14x + 8 = 0
II. 2y² + 17y + 36 = 0
I. 3x2 + 3x - 60 = 0
II. 2y2 - 7y + 5 = 0
I. 2 x ² + x – 1 = 0
II. 2 y ² - 3 y + 1 = 0
...I. y/16 = 4/y
II. x3 = (2 ÷ 50) × (2500 ÷ 50) × 42 × (192 ÷ 12)
I. 22x² - 97x + 105 = 0
II. 35y² - 61y + 24 = 0
Solve the quadratic equations and determine the relation between x and y:
Equation 1: 17x² - 94x + 120 = 0
Solve the quadratic equations and determine the relation between x and y:
Equation 1: x² - 29x + 210 = 0
Equation 2: y² - 27y + 182 = 0