Question
A container has 60 litres of a solution which is 40%
acid and 60% water. If x litres of water is added to this solution, the resulting mixture becomes 30% acid. What is the value of x?Solution
Total volume = 60 litres Acid = 40% of 60 = 24 litres Water = 36 litres After adding x litres of water: Acid remains = 24 litres (no acid added) Water = 36 + x litres Total volume = 60 + x Given new concentration of acid is 30%: Acid / Total = 30% 24 / (60 + x) = 0.30 24 = 0.30(60 + x) 24 = 18 + 0.30x 24 − 18 = 0.30x 6 = 0.30x x = 6 / 0.30 = 6 × (10/3) = 20
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