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ATQ, Let the total work be LCM of 10 and 12 = 60 units. Number of units of work done by P and Q together in one day = 60 / 10 = 6 units. Number of units of work done by Q and R together in one day = 60 / 12 = 5 units. Let Q’s daily work be ‘x’ units. Then R’s daily work is ‘1.5x’ units. So, 1.5x + x = 5 2.5x = 5 x = 5 / 2.5, x = 2 Work done by P alone in one day = 6 – 2 = 4 Required time taken by P alone to complete the work = 60 / 4 = 15 days
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