Question
A and B invests Rs. (X-1200) and (X+1800) in a business
respectively. Investment period of both of them was same. If the total profit is Rs. Y and profit share of B is 8Y/11, then find the value of X.Solution
ATQ: => (X + 1800)/(X – 1200 + X + 1800) = 8Y/11Y => (X + 1800)/(2X + 600) = 8/11 => 11(X + 1800) = 8(2X + 600) => 11X + 19800 = 16X + 4800 => 5X = 15000 => X = 3000
A sequence {Sₙ} is defined by:
Condition I: S₁ = 3 and for all n ≥ 2, Sₙ = 2·Sₙ₋₁ + (−1)ⁿ.
Condition II: The second ter...
27 44 63 86 ? 146
6 16 116 566 2272 6814
11 a�...
100, 110, ?, 171.6, 240.24, 360.36
31 16.5 18 �...
104 136 152 160 164 ?
...30 32 67 206 ? 4166
625, 5, 125, 25, 25, ? , 5
16 4 2 1.5 1 1.875
...130 155 146 195 186 ?
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