Question
A and B invests Rs. (X-1200) and (X+1800) in a business
respectively. Investment period of both of them was same. If the total profit is Rs. Y and profit share of B is 8Y/11, then find the value of X.Solution
ATQ: => (X + 1800)/(X – 1200 + X + 1800) = 8Y/11Y => (X + 1800)/(2X + 600) = 8/11 => 11(X + 1800) = 8(2X + 600) => 11X + 19800 = 16X + 4800 => 5X = 15000 => X = 3000
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If tanx+secx=3, then the number of real solutions in [0,3π] is:
{√676.12 + 13.012 – 146.89 } = ?
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In an exam Dinesh scored 362 marks and Shivam got 68 % marks in the same exam which is 12 marks more than Dinesh. If the minimum passing marks in the ex...
Find the simple interest on Rs 1040 at 12% per annum for 2 years?
The following table shows the number of students enrolled in different courses at a university:
The ages of P, Q, and R are in the ratio 2:3:5. After 5 years, the sum of their ages will be 75 years. What are their present ages?
f(x)=x+ ∣ x ∣ , then the function is:
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