Question
Let ‘x’ be the least number divisible by 16, 18, 20,
25 and 45, and also ‘x’ is a perfect square. Find the remainder when ‘x’ is divided by 88.Solution
ATQ, LCM of 16, 18, 20, 25 and 45 = 7200 Since, 7200 = (2 × 2 × 2 × 2 × 3 × 3 × 5 × 5) To make it a perfect square, multiply by ‘3’. So, desired number = 7200 × 3 = 21600 21600 ÷ 88 = 245 × 88 + 20 So, desired remainder = 20
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