Question
The sum of the average of two numbers and the third
number gives 250, 238 and 222 respectively. Find the difference between the greatest and smallest number.Solution
ATQ,
Let numbers be x, y, z. 2x + y + z = 250 × 2 = 500 x + 2y + z = 238 × 2 = 476 x + y + 2z = 222 × 2 = 444 4(x + y + z) = 500 + 476 + 444 = 1420 x + y + z = 355 x = 500 – 355 = 145 y = 476 – 355 = 121 z = 444 – 355 = 89 Difference = 145 – 89 = 56
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