Question
Five successive even integers have a sum of 260. Find
the difference between the cube of the first and the square of the last.Solution
ATQ,
x + (x+2) + (x+4) + (x+6) + (x+8) = 260
5x + 20 = 260
5x = 240
x = 48
Hence, Required difference = (48Β³ β 56Β²) = 110592 β 3136 = 107456
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