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    Question

    Five successive even integers have a sum of 260. Find

    the difference between the cube of the first and the square of the last.
    A 130168 Correct Answer Incorrect Answer
    B 107456 Correct Answer Incorrect Answer
    C 116420 Correct Answer Incorrect Answer
    D 122108 Correct Answer Incorrect Answer

    Solution

    ATQ,

    x + (x+2) + (x+4) + (x+6) + (x+8) = 260

    5x + 20 = 260

    5x = 240

    x = 48

    Hence, Required difference = (48³ – 56²) = 110592 – 3136 = 107456

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