Question
There are nine consecutive even numbers. The smallest
number is 20% less than the largest number. What is the sum of the second smallest and second largest numbers?Solution
ATQ,
Let the consecutive even numbers be: x, x + 2, x + 4, x + 6, x + 8, x + 10, x + 12, x + 14, x + 16.
According to question: x = 0.80 × (x + 16)
0.2x = 12.8
x = 64
So the desired sum = 64 + 2 + 64 + 14 = 144
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