Question
There are nine consecutive even numbers. The smallest
number is 20% less than the largest number. What is the sum of the second smallest and second largest numbers?Solution
ATQ,
Let the consecutive even numbers be: x, x + 2, x + 4, x + 6, x + 8, x + 10, x + 12, x + 14, x + 16.
According to question: x = 0.80 × (x + 16)
0.2x = 12.8
x = 64
So the desired sum = 64 + 2 + 64 + 14 = 144
 Solve: 666/6/3 = ?
95% of 830 - ? % of 2770 = 650
What will come in the place of question mark (?) in the given expression?
(30 × 5 + 20) × 2 = ?
Find the unknown value of' x' in the proportion $$(5x + 1) : 3 = (x + 3) : 7
[(√576 × √144) ÷ √1296]2 = ? ÷ 3
12.232 + 29.98% of 539.99 = ? × 5.99
1550 ÷ 62 + 54.6 x 36 = (? x 10) + (28.5 x 40)     Â
- What will come in place of (?) in the given expression.
625 + 196 – √256 = ? (72 × 52 + 1555 )/(79+60) = 2000 ÷ ?
(92.03 + 117.98) ÷ 14.211 = 89.9 – 30.23% of ?