Question
'k' is the fraction which must be subtracted from (5/6) to
get (2/9). Find the remainder when denominator of 'k' is divided by numerator of 'k'.Solution
ATQ,
'k' = (5/6) - (2/9) = (45 - 12) ÷ 54 = (33/54)
Remainder on dividing 54 by 33 = 21
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