New Enroll in RBI Grade B New Batch - Starts on May 21

    Question

    Determine the smallest 5-digit number that is divisible by

    16, 28, 32 and 40.
    A 10,508 Correct Answer Incorrect Answer
    B 10,000 Correct Answer Incorrect Answer
    C 10,080 Correct Answer Incorrect Answer
    D 10,024 Correct Answer Incorrect Answer

    Solution

    ATQ,

    LCM of 16, 28, 32 and 40 = 1120

    Least 5-digit number = 10000

    So, 10000 ÷ 1120 = 8.92

    Therefore, we should multiply 9 and 1120 to get the required 5-digit number

    So, required number = 10,080

    Practice Next

    Relevant for Exams: