Question
Determine the smallest 5-digit number that is divisible by
16, 28, 32 and 40.Solution
ATQ,
LCM of 16, 28, 32 and 40 = 1120
Least 5-digit number = 10000
So, 10000 Ă· 1120 = 8.92
Therefore, we should multiply 9 and 1120 to get the required 5-digit number
So, required number = 10,080
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