📢 Too many exams? Don’t know which one suits you best? Book Your Free Expert 👉 call Now!
  • google app store apple app store
    • ✖

      Question

      Product of two consecutive positive even numbers is

      288. Find the sum of the digits of the two numbers. 
      A 14 Correct Answer Incorrect Answer
      B 16 Correct Answer Incorrect Answer
      C 18 Correct Answer Incorrect Answer
      D 20 Correct Answer Incorrect Answer

      Solution

      Let the numbers be ( 2n ) and ( (2n + 2) ) respectively.  ATQ,  ( 2n * (2n + 2) = 288 )  Or, ( n * (2n + 2) = 144 )  Or, ( 2n² + 2n = 144 )  Or, ( n² + n = 72 )  Or, ( n² + n - 72 = 0 )  Or, ( n² + 9n - 8n - 72 = 0 )  Or, ( n(n + 9) - 8(n + 9) = 0 )  Or, ( (n + 9)(n - 8) = 0 )  So, ( n = -9 ) or ( 8 )  So, ( n = 8 )  So, numbers are ( 16 ) and ( 18 ).  Therefore, required sum = ( 1 + 6 + 1 + 8 = 16 ) 

      Practice Next
      More No. System Questions