Question
Find the smallest 5-digit number which is divisible by 12,
18, 24 and 36.Solution
ATQ,
LCM of 12, 18, 24 and 36 = 72
Least 5-digit number = 10000
So, 10000 ÷ 72 = 138.88
Therefore, we should multiply 139 and 72 to get the required 5-digit number
So, required number = 10,008
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