Question
A number when divided by 21 gives a remainder of 15.
What will be the remainder when twice that number is divided by 21?Solution
ATQ,
Number = (21A + 15), where 'A' is a constant.
Therefore, required remainder = [2 × (21A + 15)] ÷ 21
= (42A + 30) ÷ 21
= (42A + 21 + 9) ÷ 21 = 9
More No. System Questions
(225 + 125) ÷ 7 + 250 = ? + 20% of 800
32 × 3 (54 – 15) + 186 ÷ 3 ÷ 2 – (21)² = ?
193. 69 + 200.09 – 512.96 + 312.09 =?
I. x² + 3x – 154 = 0
II. y² + 5y – 126 = 0
33 + ? = 40% of 1420
[4(1/2) + 4(1/3)] × 12 – 42 = ?2
What value should come in the place of (?) in the following questions?
222 + 322 – 508 = ? * 5
181/8 + 51/4 – 63/8 = ? + 9/2
(106 + 14)/15 = ?/5
3.55 + 1.05 + 2.5 × 13 – 12% of 12.5 = ?
